Motor Current Calculator – Full Load Current (FLA/FLC)
Calculate Smarter. Work Faster.
Free motor current calculator — enter kW or HP, voltage, power factor and efficiency to get the full load current in amps for 3-phase, single-phase or DC motors, plus kVA and a typical starting-current range.
Motor Details
Fill in the motor's rated power, supply, and performance figures below.
Nameplate kW/HP is shaft output — efficiency is applied.
Enter the rated current printed on the motor nameplate at this voltage to compare it with the formula estimate and see the efficiency × PF it implies.
Estimated running current at rated output — verify against the motor nameplate
Enter your values and hit calculate to see the full breakdown.
Enter your values and hit calculate.
Protection sizing is not derived from this planning reference current. Use the motor nameplate FLC and applicable local electrical code to select conductor, overload, and branch-circuit overcurrent protection — starting current must also be considered.
How to Calculate Motor Full Load Current
Full Load Current (FLC), also called Full Load Amps (FLA), is the steady running current at rated output. It is the starting figure for cable, contactor and overload selection.
This tool works as a kW to amps, HP to amps and FLA calculator for 3-phase, single-phase and DC motors at any voltage up to 1000 V. For heaters and other non-motor loads, use the kW to Current Calculator.
Motor Current Formula
I = current (A) · kW = rated shaft output · V = voltage (line-to-line for 3-phase) · PF = power factor · η = efficiency as a decimal.
Motor Current Examples
7.5 kW 3-phase motor, 415 V
PF 0.85, efficiency 90%.
I ≈ 13.6 A
15 kW motor, 400 V 3-phase
PF 0.85, efficiency 90%.
I ≈ 28.3 A
30 HP motor, 415 V 3-phase
30 HP × 746 = 22,380 W; PF 0.85, η 90%.
I ≈ 40.7 A
160 kW motor, 415 V 3-phase
Large motor: PF 0.88, efficiency 95%.
I ≈ 266 A
1 kW single-phase motor, 230 V
Small motor: PF 0.80, efficiency 80%.
I ≈ 6.8 A
7.5 kW starting current (DOL)
FLC ≈ 13.6 A; DOL inrush typically 5–8× FLC.
≈ 68 – 109 A (brief)
Motor Current Table: kW to Amps (3-Phase)
Estimated full-load current at PF 0.85 and 90% efficiency — the calculator defaults, so you can reproduce any row. Scroll inside the table.
| Motor (kW) | ≈ HP | 380 V | 400 V | 415 V | 440 V |
|---|---|---|---|---|---|
| 0.37 kW | 0.5 | 0.7 A | 0.7 A | 0.7 A | 0.6 A |
| 0.55 kW | 0.7 | 1.1 A | 1.0 A | 1.0 A | 0.9 A |
| 0.75 kW | 1.0 | 1.5 A | 1.4 A | 1.4 A | 1.3 A |
| 1.1 kW | 1.5 | 2.2 A | 2.1 A | 2.0 A | 1.9 A |
| 1.5 kW | 2.0 | 3.0 A | 2.8 A | 2.7 A | 2.6 A |
| 2.2 kW | 2.9 | 4.4 A | 4.2 A | 4.0 A | 3.8 A |
| 3 kW | 4.0 | 6.0 A | 5.7 A | 5.5 A | 5.1 A |
| 3.7 kW | 5.0 | 7.3 A | 7.0 A | 6.7 A | 6.3 A |
| 4 kW | 5.4 | 7.9 A | 7.5 A | 7.3 A | 6.9 A |
| 5.5 kW | 7.4 | 10.9 A | 10.4 A | 10.0 A | 9.4 A |
| 7.5 kW | 10.1 | 14.9 A | 14.2 A | 13.6 A | 12.9 A |
| 11 kW | 14.7 | 21.8 A | 20.8 A | 20.0 A | 18.9 A |
| 15 kW | 20.1 | 29.8 A | 28.3 A | 27.3 A | 25.7 A |
| 18.5 kW | 24.8 | 36.7 A | 34.9 A | 33.6 A | 31.7 A |
| 22 kW | 29.5 | 43.7 A | 41.5 A | 40.0 A | 37.7 A |
| 30 kW | 40.2 | 59.6 A | 56.6 A | 54.6 A | 51.5 A |
| 37 kW | 49.6 | 73.5 A | 69.8 A | 67.3 A | 63.5 A |
| 45 kW | 60.3 | 89.4 A | 84.9 A | 81.8 A | 77.2 A |
| 55 kW | 73.7 | 109.2 A | 103.8 A | 100.0 A | 94.3 A |
| 75 kW | 100.5 | 149.0 A | 141.5 A | 136.4 A | 128.6 A |
| 90 kW | 120.6 | 178.8 A | 169.8 A | 163.7 A | 154.4 A |
| 110 kW | 147.5 | 218.5 A | 207.6 A | 200.0 A | 188.7 A |
| 132 kW | 176.9 | 262.2 A | 249.1 A | 240.1 A | 226.4 A |
| 160 kW | 214.5 | 317.8 A | 301.9 A | 291.0 A | 274.4 A |
These are estimated running-current values based on assumed PF and efficiency. Small motors usually have lower PF and efficiency, so their real FLC is often higher than shown. Actual full-load current depends on nameplate data, design, voltage and operating conditions — use the nameplate and applicable standards for final design.
Single-Phase Motor Current Table
Small single-phase motors run at lower PF and efficiency. This table assumes PF 0.80 and 80% efficiency.
| Motor (kW) | ≈ HP | 120 V | 230 V | 240 V |
|---|---|---|---|---|
| 0.18 kW | 0.24 | 2.3 A | 1.2 A | 1.2 A |
| 0.25 kW | 0.34 | 3.3 A | 1.7 A | 1.6 A |
| 0.37 kW | 0.50 | 4.8 A | 2.5 A | 2.4 A |
| 0.55 kW | 0.74 | 7.2 A | 3.7 A | 3.6 A |
| 0.75 kW | 1.01 | 9.8 A | 5.1 A | 4.9 A |
| 1.1 kW | 1.47 | 14.3 A | 7.5 A | 7.2 A |
| 1.5 kW | 2.01 | 19.5 A | 10.2 A | 9.8 A |
| 2.2 kW | 2.95 | 28.6 A | 14.9 A | 14.3 A |
| 3 kW | 4.02 | 39.1 A | 20.4 A | 19.5 A |
| 3.7 kW | 4.96 | 48.2 A | 25.1 A | 24.1 A |
Illustrative estimates only. Capacitor-start and capacitor-run motors differ — check the nameplate.
Motor Current Examples by Region
Typical supply voltages worldwide, calculated at PF 0.85 and 90% efficiency.
| Example | Motor Rating | Supply | FLC (A) |
|---|---|---|---|
| USA | 10 HP | 460V, 3-phase | ≈12.2 A |
| Canada | 20 HP | 600V, 3-phase | ≈18.8 A |
| UK / Europe | 15 kW | 400V, 3-phase | ≈28.3 A |
| Australia | 11 kW | 400V, 3-phase | ≈20.8 A |
| UAE / Saudi Arabia | 30 kW | 400V, 3-phase | ≈56.6 A |
| India | 15 kW | 415V, 3-phase | ≈27.3 A |
FLA vs FLC vs Rated Current
Why a Formula Estimate Differs from the Nameplate FLA
The formula is exact physics, but its inputs are assumptions. Current is inversely proportional to efficiency × power factor, and both vary with rating, pole count, design and efficiency class: small and low-speed motors run at noticeably lower power factor and efficiency than large two- and four-pole machines, so a single PF 0.85 / 90% assumption underestimates small-motor current and can slightly overestimate large-motor current. For reference, the IE3 minimum efficiencies in IEC 60034-30-1 for four-pole 50 Hz motors rise from about 82.5% at 0.75 kW to about 91.4% at 11 kW and 95% at 75 kW; the calculator shows the IE3 figure for your rating when a three-phase shaft-output rating is entered, so you can see how far your efficiency assumption is from it. Power factor has no equivalent standard minimum and must come from the data sheet.
If you enter the nameplate FLA in the cross-check field, the calculator back-calculates the efficiency × power factor product the nameplate implies: η·PF = P ÷ (√3 × V × I) for three-phase. A plausible result (roughly 0.6–0.9 depending on size) confirms the reading; a result far outside that range usually means the wrong voltage column of a dual-voltage nameplate, an HP/kW mix-up, or a service-factor amps value read as FLA. Whenever the nameplate is available, it — not the formula — is the value for overload settings and equipment selection under IEC practice; under the US NEC, conductors and short-circuit protection use the code table FLC instead, as explained below.
Why FLC Drives Every Downstream Choice
Cable: needs enough ampacity for the installation method, ambient temperature, grouping and voltage drop — size it with the Cable Size Calculator, then check the run with the Voltage Drop Calculator.
Contactor: rated for the motor current under AC-3 duty.
Overload relay: set from the nameplate current, relay class and code/manufacturer rules.
Short-circuit protection: chosen per code and must ride through starting current (often 5–8× FLC for DOL).
How to Use This Calculator
- Pick Three Phase, Single Phase or DC.
- Enter rated power in kW or HP, and choose shaft output or electrical input.
- Enter voltage, PF and efficiency (nameplate values if available; 0.85 PF and 88–92% are typical planning values for mid-size motors).
- Choose a starting method to see a typical inrush range. Results update as you type.
Common Mistakes
- Forgetting efficiency. Using shaft kW as input power understates FLC by 10% or more.
- Dividing by efficiency twice. If your kW is already electrical input, don't apply η again.
- One PF for every size. Small and lightly loaded motors run at lower PF.
- Missing or wrongly adding √3. The error is a factor of about 1.73.
- Treating a fixed % as code sizing. Allowances depend on local code and starter type.
NEC FLC Table vs Actual Motor FLA
Under the US NEC, conductor and short-circuit protection sizing for most motors uses the standardised FLC tables, not the nameplate. Overload protection uses the nameplate FLA.
Table values are fixed per HP and voltage, so they differ from a formula result using a specific motor's PF and efficiency. Low-speed, high-torque and multispeed motors use nameplate values instead.
Three-phase induction motors — selected NEC Table 430.250 values (A):
| HP | 208 V | 230 V | 460 V | 575 V |
|---|---|---|---|---|
| 1 HP | 4.6 | 4.2 | 2.1 | 1.7 |
| 2 HP | 7.5 | 6.8 | 3.4 | 2.7 |
| 3 HP | 10.6 | 9.6 | 4.8 | 3.9 |
| 5 HP | 16.7 | 15.2 | 7.6 | 6.1 |
| 7½ HP | 24.2 | 22 | 11 | 9 |
| 10 HP | 30.8 | 28 | 14 | 11 |
| 15 HP | 46.2 | 42 | 21 | 17 |
| 20 HP | 59.4 | 54 | 27 | 22 |
| 25 HP | 74.8 | 68 | 34 | 27 |
| 30 HP | 88 | 80 | 40 | 32 |
| 40 HP | 114 | 104 | 52 | 41 |
| 50 HP | 143 | 130 | 65 | 52 |
| 60 HP | 169 | 154 | 77 | 62 |
| 75 HP | 211 | 192 | 96 | 77 |
| 100 HP | 273 | 248 | 124 | 99 |
| 125 HP | 343 | 312 | 156 | 125 |
| 150 HP | 396 | 360 | 180 | 144 |
| 200 HP | 528 | 480 | 240 | 192 |
Single-phase motors — selected NEC Table 430.248 values (A):
| HP | 115 V | 208 V | 230 V |
|---|---|---|---|
| ½ HP | 9.8 | 5.4 | 4.9 |
| ¾ HP | 13.8 | 7.6 | 6.9 |
| 1 HP | 16 | 8.8 | 8 |
| 1½ HP | 20 | 11 | 10 |
| 2 HP | 24 | 13.2 | 12 |
| 3 HP | 34 | 18.7 | 17 |
| 5 HP | 56 | 30.8 | 28 |
| 7½ HP | 80 | 44 | 40 |
| 10 HP | 100 | 55 | 50 |
Selected values for reference; the 230 V column applies to 220–240 V systems and 460 V to 440–480 V. Confirm against the NEC edition adopted in your jurisdiction. In Canada, apply CSA C22.1 requirements for the applicable edition. Do not mix these US table values with IEC/BIS practice.
Quick NEC answers: 15 HP, 240 V 3-phase → 42 A · 10 HP, 208 V 3-phase → 30.8 A · 5 HP, 208 V single-phase → 30.8 A · 200 HP, 460 V → 240 A · 75 HP, 480 V → 96 A.
Finding the FLA of a Specific Motor Model
Catalog numbers (like those printed on NEMA-frame or DC motors) map to one manufacturer datasheet. A generic formula cannot give that exact value.
Read the nameplate or the manufacturer's datasheet at the connected voltage. Note FLA, SFA, service factor, code letter, efficiency and PF — then use this calculator only to cross-check.
MCA vs FLA
MCA (Minimum Circuit Ampacity) on HVAC and packaged equipment is a code-derived conductor figure. It typically includes 125% of the largest motor plus other loads, so it cannot be converted back to one motor's FLA. Use the FLA/RLA values on the same nameplate.
How Starting Method Affects Inrush Current
FLC is the running current. At start, an induction motor briefly draws far more — how much depends on motor design, supply strength and starting method.
| Starting Method | Typical Inrush | Starting Torque |
|---|---|---|
| Direct-On-Line (DOL) | 5–8× FLA | Full (100%) |
| Star-Delta | Typically ~2–3× FLA at the supply, depending on motor and system conditions | ~33% of DOL |
| Auto-transformer | 1.7–4× FLA (tap-dependent) | Tap-dependent |
| Soft starter | Commonly configurable ~2–4× FLA, depending on current-limit setting, motor and load | Adjustable, smooth ramp |
| VFD (Variable Frequency Drive) | Typically ~1–1.5× FLA with properly configured drive control | Depends on VFD control mode, motor, and load |
DOL is simplest and cheapest but gives the highest inrush and mechanical shock — fine for small motors on a strong supply.
Star-delta, soft starters and VFDs reduce inrush, protect belts and couplings, and limit voltage dips for larger motors or weak supplies.
The calculator's starting range is a typical estimate only. For a real figure, use the locked-rotor current from the nameplate code letter or datasheet, or the Motor Starting Current Calculator.
Frequently Asked Questions
Content last reviewed: September 2026
How do you calculate motor full load current (FLA)? +
Three-phase: I = (kW × 1000) ÷ (1.732 × V × PF × η). Single-phase: I = (kW × 1000) ÷ (V × PF × η). Here kW is the rated shaft output and η is efficiency as a decimal. Example: 15 kW at 415 V, PF 0.85, 90% efficiency ≈ 27.3 A. For HP, multiply by 746 to get watts first.
Should I use the calculated current or the motor's nameplate FLC? +
Prefer the nameplate FLC/FLA whenever it is available — it reflects that motor's tested design. Use the calculated value when the nameplate is missing, to cross-check a suspicious value, or before a motor model is chosen.
Why is my calculated current different from the motor nameplate FLA? +
Because the formula depends on the efficiency and power factor you assume, and real values vary with rating, pole count and design. Small motors typically have lower PF and efficiency than the 0.85 / 90% defaults, so their nameplate current is higher than the estimate. Enter the nameplate FLA in the cross-check field to see the efficiency × PF it implies; a value far outside roughly 0.6–0.9 usually points to a wrong voltage column, an HP/kW mix-up or a service-factor amps value. The nameplate always takes priority.
Should I enter the motor's output kW or input kW? +
Nameplate kW or HP is mechanical shaft output, so divide by efficiency. If you already know the electrical input kW (for example from a power meter), choose "Electrical input" in the calculator — efficiency must not be applied a second time.
What is the full-load current of a 3-phase motor? +
It depends on voltage, power, efficiency and PF. At PF 0.85 and 90% efficiency, a 3-phase motor draws roughly 1.8-1.9 A per kW at 400-415 V (real small motors draw more), and proportionally less at 460 V or 600 V. For example, 15 kW at 415 V ≈ 27.3 A; 10 HP at 460 V ≈ 12.2 A.
What is the full load current of a 50 HP motor? +
By formula (PF 0.85, 90% efficiency) a 50 HP (37.3 kW) motor draws about 67.8 A at 415 V and about 61.2 A at 460 V. For US code work, NEC Table 430.250 lists 65 A at 460 V and 130 A at 230 V for a 50 HP three-phase induction motor.
What is the difference between FLA and FLC? +
Both mean full-load current. FLA (full-load amps) usually refers to the motor nameplate value. In NEC work, FLC often means the standardised value from Table 430.248/430.250, which is used for conductor and short-circuit protection sizing, while the nameplate FLA is used for overload protection.
Why does a three-phase motor draw less current than a single-phase motor of the same power? +
The √3 factor means three-phase power is shared across three line conductors. The same power therefore needs less current per line, allowing smaller cable and switchgear.
Why is efficiency used to calculate current, since current relates to input power? +
Nameplate power is mechanical output. Losses in the windings, core and bearings make electrical input higher than output, so dividing by efficiency converts rated output to the real electrical input used in the current formula.
Why does a motor draw so much more current when starting than when running? +
At standstill the rotor acts like a short-circuited transformer winding, so impedance is very low until the motor builds speed. DOL starting current is typically 5-8× FLC, depending on motor design and supply — which is why reduced-voltage starters, soft starters and VFDs exist.
Should I size the breaker for FLA or for starting inrush current? +
Neither alone. Overload protection is set close to nameplate FLA. Short-circuit/ground-fault protection is selected per the applicable code and must tolerate the permitted starting current without nuisance tripping. Exact devices and settings depend on local code and starting method.
What is the no-load current of an induction motor? +
No-load current is mainly magnetising current. It varies widely with motor design and size — small motors often run at a much higher percentage of FLC on no load than large motors. Measure it or use manufacturer test data rather than a fixed rule.
Can I convert MCA to FLA? +
Not reliably. MCA (minimum circuit ampacity, common on HVAC nameplates) is a code-derived conductor figure that typically includes 125% of the largest motor plus other loads. Use the individual motor FLA or RLA values printed on the equipment nameplate instead.
How do I find the FLA of a specific motor model or catalog number? +
Check the motor nameplate or the manufacturer's datasheet for that catalog number, at the exact voltage the motor is connected to. Dual-voltage motors list a different FLA for each voltage, and some also list a service-factor amps (SFA) value. Do not rely on a generic estimate for a specific model.
Does power factor correction change the motor's FLC? +
Capacitors reduce the reactive current drawn upstream of the correction point, lowering line current and kVA seen by the supply. They do not change the current in the motor windings. One practical consequence: if capacitors are connected at the motor terminals on the load side of the overload relay, the relay sees the reduced current, so its setting must be based on the winding current (per the manufacturer's or code's adjustment rules), not simply on the nameplate FLA. Use the APFC Capacitor Calculator to size correction.
Can this calculator be used for DC motors? +
Yes — select DC. For a DC motor, I = (kW × 1000) ÷ (V × η), with no power factor or √3. Starting current of a DC motor depends on armature resistance and the starter used, so it is not estimated here.