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Motor Current Calculator – Full Load Current (FLA/FLC)

Calculate Smarter. Work Faster.

Free motor current calculator — enter kW or HP, voltage, power factor and efficiency to get the full load current in amps for 3-phase, single-phase or DC motors, plus kVA and a typical starting-current range.

Motor Details

Fill in the motor's rated power, supply, and performance figures below.

Supply Type
Power Unit
Power Basis

Nameplate kW/HP is shaft output — efficiency is applied.

Common Voltages

Enter the rated current printed on the motor nameplate at this voltage to compare it with the formula estimate and see the efficiency × PF it implies.

3-ph: I = P ÷ (√3 × V × PF × η) 1-ph: I = P ÷ (V × PF × η) DC: I = P ÷ (V × η) 1 HP = 746 W
Estimated Full Load Current
— A

Estimated running current at rated output — verify against the motor nameplate

Power (kW)
— kW
Power (HP)
— HP
Apparent Power
— kVA
Input Power Drawn
— kW
Planning Reference Current
— A
Est. Starting Current
— A
Formula Used

Enter your values and hit calculate to see the full breakdown.

Estimate Checks

Enter your values and hit calculate.

Protection Sizing Note

Protection sizing is not derived from this planning reference current. Use the motor nameplate FLC and applicable local electrical code to select conductor, overload, and branch-circuit overcurrent protection — starting current must also be considered.

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Created by Umasankar Maity — B.Tech in Electrical Engineering, with 11+ years of industrial maintenance experience.

Reviewed by the ElectroMechCalc editorial team.

Last reviewed: September 2026  |  Method: Generic current calculation using the standard three-phase power relationship P = √3 × V × I × PF, with motor efficiency applied when converting rated mechanical output to electrical input. This is a universal physics relationship, not a code-specific sizing procedure — codes such as IEC, IEEE, BIS, and NEC may prescribe their own FLA tables and load calculation rules, which are not automatically applied here. For code-compliant design, use the motor nameplate FLA or the applicable requirements of the governing electrical standard.

How it works

How to Calculate Motor Full Load Current

Quick answer: three-phase motor FLC = kW × 1000 ÷ (1.732 × V × PF × η). Example: 15 kW at 415 V, PF 0.85, 90% efficiency ≈ 27.3 A.

Full Load Current (FLC), also called Full Load Amps (FLA), is the steady running current at rated output. It is the starting figure for cable, contactor and overload selection.

This tool works as a kW to amps, HP to amps and FLA calculator for 3-phase, single-phase and DC motors at any voltage up to 1000 V. For heaters and other non-motor loads, use the kW to Current Calculator.

Motor Current Formula

Three-phase motor (shaft kW)
I =kW × 1000√3 × V × PF × η
Single-phase motor (shaft kW)
I =kW × 1000V × PF × η
Known electrical input kW (3-phase)
I =kWin × 1000√3 × V × PF
DC motor
I =kW × 1000V × η
HP to watts
P (W) = HP × 746

I = current (A) · kW = rated shaft output · V = voltage (line-to-line for 3-phase) · PF = power factor · η = efficiency as a decimal.

Output vs input kW: nameplate kW/HP is mechanical output, so divide by η. If you already know the electrical input kW (from a meter), do not divide by η again — use the “Electrical input” option.

Motor Current Examples

7.5 kW 3-phase motor, 415 V

PF 0.85, efficiency 90%.

I = 7500 ÷ (1.732 × 415 × 0.85 × 0.90)

I ≈ 13.6 A

15 kW motor, 400 V 3-phase

PF 0.85, efficiency 90%.

I = 15000 ÷ (1.732 × 400 × 0.85 × 0.90)

I ≈ 28.3 A

30 HP motor, 415 V 3-phase

30 HP × 746 = 22,380 W; PF 0.85, η 90%.

I = 22380 ÷ (1.732 × 415 × 0.85 × 0.90)

I ≈ 40.7 A

160 kW motor, 415 V 3-phase

Large motor: PF 0.88, efficiency 95%.

I = 160000 ÷ (1.732 × 415 × 0.88 × 0.95)

I ≈ 266 A

1 kW single-phase motor, 230 V

Small motor: PF 0.80, efficiency 80%.

I = 1000 ÷ (230 × 0.80 × 0.80)

I ≈ 6.8 A

7.5 kW starting current (DOL)

FLC ≈ 13.6 A; DOL inrush typically 5–8× FLC.

13.6 × 5 → 13.6 × 8

≈ 68 – 109 A (brief)

Motor Current Table: kW to Amps (3-Phase)

Estimated full-load current at PF 0.85 and 90% efficiency — the calculator defaults, so you can reproduce any row. Scroll inside the table.

Motor (kW)≈ HP380 V400 V415 V440 V
0.37 kW0.50.7 A0.7 A0.7 A0.6 A
0.55 kW0.71.1 A1.0 A1.0 A0.9 A
0.75 kW1.01.5 A1.4 A1.4 A1.3 A
1.1 kW1.52.2 A2.1 A2.0 A1.9 A
1.5 kW2.03.0 A2.8 A2.7 A2.6 A
2.2 kW2.94.4 A4.2 A4.0 A3.8 A
3 kW4.06.0 A5.7 A5.5 A5.1 A
3.7 kW5.07.3 A7.0 A6.7 A6.3 A
4 kW5.47.9 A7.5 A7.3 A6.9 A
5.5 kW7.410.9 A10.4 A10.0 A9.4 A
7.5 kW10.114.9 A14.2 A13.6 A12.9 A
11 kW14.721.8 A20.8 A20.0 A18.9 A
15 kW20.129.8 A28.3 A27.3 A25.7 A
18.5 kW24.836.7 A34.9 A33.6 A31.7 A
22 kW29.543.7 A41.5 A40.0 A37.7 A
30 kW40.259.6 A56.6 A54.6 A51.5 A
37 kW49.673.5 A69.8 A67.3 A63.5 A
45 kW60.389.4 A84.9 A81.8 A77.2 A
55 kW73.7109.2 A103.8 A100.0 A94.3 A
75 kW100.5149.0 A141.5 A136.4 A128.6 A
90 kW120.6178.8 A169.8 A163.7 A154.4 A
110 kW147.5218.5 A207.6 A200.0 A188.7 A
132 kW176.9262.2 A249.1 A240.1 A226.4 A
160 kW214.5317.8 A301.9 A291.0 A274.4 A

These are estimated running-current values based on assumed PF and efficiency. Small motors usually have lower PF and efficiency, so their real FLC is often higher than shown. Actual full-load current depends on nameplate data, design, voltage and operating conditions — use the nameplate and applicable standards for final design.

Single-Phase Motor Current Table

Small single-phase motors run at lower PF and efficiency. This table assumes PF 0.80 and 80% efficiency.

Motor (kW)≈ HP120 V230 V240 V
0.18 kW0.242.3 A1.2 A1.2 A
0.25 kW0.343.3 A1.7 A1.6 A
0.37 kW0.504.8 A2.5 A2.4 A
0.55 kW0.747.2 A3.7 A3.6 A
0.75 kW1.019.8 A5.1 A4.9 A
1.1 kW1.4714.3 A7.5 A7.2 A
1.5 kW2.0119.5 A10.2 A9.8 A
2.2 kW2.9528.6 A14.9 A14.3 A
3 kW4.0239.1 A20.4 A19.5 A
3.7 kW4.9648.2 A25.1 A24.1 A

Illustrative estimates only. Capacitor-start and capacitor-run motors differ — check the nameplate.

Motor Current Examples by Region

Typical supply voltages worldwide, calculated at PF 0.85 and 90% efficiency.

ExampleMotor RatingSupplyFLC (A)
USA10 HP460V, 3-phase≈12.2 A
Canada20 HP600V, 3-phase≈18.8 A
UK / Europe15 kW400V, 3-phase≈28.3 A
Australia11 kW400V, 3-phase≈20.8 A
UAE / Saudi Arabia30 kW400V, 3-phase≈56.6 A
India15 kW415V, 3-phase≈27.3 A

FLA vs FLC vs Rated Current

FLA — Full-Load AmpsThe current a motor draws at rated output, voltage and frequency. Usually the value printed on the nameplate.
FLC — Full-Load CurrentSame idea. In NEC work, FLC often means the standardised table value (Tables 430.248/430.250), which can differ from nameplate FLA.
Rated currentThe manufacturer's nameplate current at the stated voltage. Dual-voltage motors list one value per voltage.
SFA — Service-Factor AmpsCurrent at service-factor load (e.g. SF 1.15). Higher than FLA; not the normal running current.
Starting / locked-rotor current (LRA)The large current at standstill and during acceleration. Set by motor design (NEMA code letter / IEC IL/IN ratio), supply and starting method — not by FLA alone.
No-load currentMostly magnetising current when running unloaded. Varies widely by design and size.

Why a Formula Estimate Differs from the Nameplate FLA

The formula is exact physics, but its inputs are assumptions. Current is inversely proportional to efficiency × power factor, and both vary with rating, pole count, design and efficiency class: small and low-speed motors run at noticeably lower power factor and efficiency than large two- and four-pole machines, so a single PF 0.85 / 90% assumption underestimates small-motor current and can slightly overestimate large-motor current. For reference, the IE3 minimum efficiencies in IEC 60034-30-1 for four-pole 50 Hz motors rise from about 82.5% at 0.75 kW to about 91.4% at 11 kW and 95% at 75 kW; the calculator shows the IE3 figure for your rating when a three-phase shaft-output rating is entered, so you can see how far your efficiency assumption is from it. Power factor has no equivalent standard minimum and must come from the data sheet.

If you enter the nameplate FLA in the cross-check field, the calculator back-calculates the efficiency × power factor product the nameplate implies: η·PF = P ÷ (√3 × V × I) for three-phase. A plausible result (roughly 0.6–0.9 depending on size) confirms the reading; a result far outside that range usually means the wrong voltage column of a dual-voltage nameplate, an HP/kW mix-up, or a service-factor amps value read as FLA. Whenever the nameplate is available, it — not the formula — is the value for overload settings and equipment selection under IEC practice; under the US NEC, conductors and short-circuit protection use the code table FLC instead, as explained below.

Why FLC Drives Every Downstream Choice

Cable: needs enough ampacity for the installation method, ambient temperature, grouping and voltage drop — size it with the Cable Size Calculator, then check the run with the Voltage Drop Calculator.

Contactor: rated for the motor current under AC-3 duty.

Overload relay: set from the nameplate current, relay class and code/manufacturer rules.

Short-circuit protection: chosen per code and must ride through starting current (often 5–8× FLC for DOL).

How to Use This Calculator

  1. Pick Three Phase, Single Phase or DC.
  2. Enter rated power in kW or HP, and choose shaft output or electrical input.
  3. Enter voltage, PF and efficiency (nameplate values if available; 0.85 PF and 88–92% are typical planning values for mid-size motors).
  4. Choose a starting method to see a typical inrush range. Results update as you type.

Common Mistakes

  • Forgetting efficiency. Using shaft kW as input power understates FLC by 10% or more.
  • Dividing by efficiency twice. If your kW is already electrical input, don't apply η again.
  • One PF for every size. Small and lightly loaded motors run at lower PF.
  • Missing or wrongly adding √3. The error is a factor of about 1.73.
  • Treating a fixed % as code sizing. Allowances depend on local code and starter type.

NEC FLC Table vs Actual Motor FLA

Under the US NEC, conductor and short-circuit protection sizing for most motors uses the standardised FLC tables, not the nameplate. Overload protection uses the nameplate FLA.

Table values are fixed per HP and voltage, so they differ from a formula result using a specific motor's PF and efficiency. Low-speed, high-torque and multispeed motors use nameplate values instead.

Three-phase induction motors — selected NEC Table 430.250 values (A):

HP208 V230 V460 V575 V
1 HP4.64.22.11.7
2 HP7.56.83.42.7
3 HP10.69.64.83.9
5 HP16.715.27.66.1
7½ HP24.222119
10 HP30.8281411
15 HP46.2422117
20 HP59.4542722
25 HP74.8683427
30 HP88804032
40 HP1141045241
50 HP1431306552
60 HP1691547762
75 HP2111929677
100 HP27324812499
125 HP343312156125
150 HP396360180144
200 HP528480240192

Single-phase motors — selected NEC Table 430.248 values (A):

HP115 V208 V230 V
½ HP9.85.44.9
¾ HP13.87.66.9
1 HP168.88
1½ HP201110
2 HP2413.212
3 HP3418.717
5 HP5630.828
7½ HP804440
10 HP1005550

Selected values for reference; the 230 V column applies to 220–240 V systems and 460 V to 440–480 V. Confirm against the NEC edition adopted in your jurisdiction. In Canada, apply CSA C22.1 requirements for the applicable edition. Do not mix these US table values with IEC/BIS practice.

Quick NEC answers: 15 HP, 240 V 3-phase → 42 A · 10 HP, 208 V 3-phase → 30.8 A · 5 HP, 208 V single-phase → 30.8 A · 200 HP, 460 V → 240 A · 75 HP, 480 V → 96 A.

Finding the FLA of a Specific Motor Model

Catalog numbers (like those printed on NEMA-frame or DC motors) map to one manufacturer datasheet. A generic formula cannot give that exact value.

Read the nameplate or the manufacturer's datasheet at the connected voltage. Note FLA, SFA, service factor, code letter, efficiency and PF — then use this calculator only to cross-check.

MCA vs FLA

MCA (Minimum Circuit Ampacity) on HVAC and packaged equipment is a code-derived conductor figure. It typically includes 125% of the largest motor plus other loads, so it cannot be converted back to one motor's FLA. Use the FLA/RLA values on the same nameplate.

Starting Methods

How Starting Method Affects Inrush Current

FLC is the running current. At start, an induction motor briefly draws far more — how much depends on motor design, supply strength and starting method.

Starting Method Typical Inrush Starting Torque
Direct-On-Line (DOL)5–8× FLAFull (100%)
Star-DeltaTypically ~2–3× FLA at the supply, depending on motor and system conditions~33% of DOL
Auto-transformer1.7–4× FLA (tap-dependent)Tap-dependent
Soft starterCommonly configurable ~2–4× FLA, depending on current-limit setting, motor and loadAdjustable, smooth ramp
VFD (Variable Frequency Drive)Typically ~1–1.5× FLA with properly configured drive controlDepends on VFD control mode, motor, and load

DOL is simplest and cheapest but gives the highest inrush and mechanical shock — fine for small motors on a strong supply.

Star-delta, soft starters and VFDs reduce inrush, protect belts and couplings, and limit voltage dips for larger motors or weak supplies.

The calculator's starting range is a typical estimate only. For a real figure, use the locked-rotor current from the nameplate code letter or datasheet, or the Motor Starting Current Calculator.

FAQ

Frequently Asked Questions

Content last reviewed: September 2026

How do you calculate motor full load current (FLA)? +

Three-phase: I = (kW × 1000) ÷ (1.732 × V × PF × η). Single-phase: I = (kW × 1000) ÷ (V × PF × η). Here kW is the rated shaft output and η is efficiency as a decimal. Example: 15 kW at 415 V, PF 0.85, 90% efficiency ≈ 27.3 A. For HP, multiply by 746 to get watts first.

Should I use the calculated current or the motor's nameplate FLC? +

Prefer the nameplate FLC/FLA whenever it is available — it reflects that motor's tested design. Use the calculated value when the nameplate is missing, to cross-check a suspicious value, or before a motor model is chosen.

Why is my calculated current different from the motor nameplate FLA? +

Because the formula depends on the efficiency and power factor you assume, and real values vary with rating, pole count and design. Small motors typically have lower PF and efficiency than the 0.85 / 90% defaults, so their nameplate current is higher than the estimate. Enter the nameplate FLA in the cross-check field to see the efficiency × PF it implies; a value far outside roughly 0.6–0.9 usually points to a wrong voltage column, an HP/kW mix-up or a service-factor amps value. The nameplate always takes priority.

Should I enter the motor's output kW or input kW? +

Nameplate kW or HP is mechanical shaft output, so divide by efficiency. If you already know the electrical input kW (for example from a power meter), choose "Electrical input" in the calculator — efficiency must not be applied a second time.

What is the full-load current of a 3-phase motor? +

It depends on voltage, power, efficiency and PF. At PF 0.85 and 90% efficiency, a 3-phase motor draws roughly 1.8-1.9 A per kW at 400-415 V (real small motors draw more), and proportionally less at 460 V or 600 V. For example, 15 kW at 415 V ≈ 27.3 A; 10 HP at 460 V ≈ 12.2 A.

What is the full load current of a 50 HP motor? +

By formula (PF 0.85, 90% efficiency) a 50 HP (37.3 kW) motor draws about 67.8 A at 415 V and about 61.2 A at 460 V. For US code work, NEC Table 430.250 lists 65 A at 460 V and 130 A at 230 V for a 50 HP three-phase induction motor.

What is the difference between FLA and FLC? +

Both mean full-load current. FLA (full-load amps) usually refers to the motor nameplate value. In NEC work, FLC often means the standardised value from Table 430.248/430.250, which is used for conductor and short-circuit protection sizing, while the nameplate FLA is used for overload protection.

Why does a three-phase motor draw less current than a single-phase motor of the same power? +

The √3 factor means three-phase power is shared across three line conductors. The same power therefore needs less current per line, allowing smaller cable and switchgear.

Why is efficiency used to calculate current, since current relates to input power? +

Nameplate power is mechanical output. Losses in the windings, core and bearings make electrical input higher than output, so dividing by efficiency converts rated output to the real electrical input used in the current formula.

Why does a motor draw so much more current when starting than when running? +

At standstill the rotor acts like a short-circuited transformer winding, so impedance is very low until the motor builds speed. DOL starting current is typically 5-8× FLC, depending on motor design and supply — which is why reduced-voltage starters, soft starters and VFDs exist.

Should I size the breaker for FLA or for starting inrush current? +

Neither alone. Overload protection is set close to nameplate FLA. Short-circuit/ground-fault protection is selected per the applicable code and must tolerate the permitted starting current without nuisance tripping. Exact devices and settings depend on local code and starting method.

What is the no-load current of an induction motor? +

No-load current is mainly magnetising current. It varies widely with motor design and size — small motors often run at a much higher percentage of FLC on no load than large motors. Measure it or use manufacturer test data rather than a fixed rule.

Can I convert MCA to FLA? +

Not reliably. MCA (minimum circuit ampacity, common on HVAC nameplates) is a code-derived conductor figure that typically includes 125% of the largest motor plus other loads. Use the individual motor FLA or RLA values printed on the equipment nameplate instead.

How do I find the FLA of a specific motor model or catalog number? +

Check the motor nameplate or the manufacturer's datasheet for that catalog number, at the exact voltage the motor is connected to. Dual-voltage motors list a different FLA for each voltage, and some also list a service-factor amps (SFA) value. Do not rely on a generic estimate for a specific model.

Does power factor correction change the motor's FLC? +

Capacitors reduce the reactive current drawn upstream of the correction point, lowering line current and kVA seen by the supply. They do not change the current in the motor windings. One practical consequence: if capacitors are connected at the motor terminals on the load side of the overload relay, the relay sees the reduced current, so its setting must be based on the winding current (per the manufacturer's or code's adjustment rules), not simply on the nameplate FLA. Use the APFC Capacitor Calculator to size correction.

Can this calculator be used for DC motors? +

Yes — select DC. For a DC motor, I = (kW × 1000) ÷ (V × η), with no power factor or √3. Starting current of a DC motor depends on armature resistance and the starter used, so it is not estimated here.

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